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-.009t^2+3.15t-135=0
We add all the numbers together, and all the variables
-0.009t^2+3.15t-135=0
a = -0.009; b = 3.15; c = -135;
Δ = b2-4ac
Δ = 3.152-4·(-0.009)·(-135)
Δ = 5.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.15)-\sqrt{5.0625}}{2*-0.009}=\frac{-3.15-\sqrt{5.0625}}{-0.018} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.15)+\sqrt{5.0625}}{2*-0.009}=\frac{-3.15+\sqrt{5.0625}}{-0.018} $
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